I understand it's not polite to bluntly ask for anybody to make a script that i need, so hope asomebody can give hints on commands i must use to try to achieve my goal.
The goal is a a script that makes automatic deletion of GIF frames(layers) based on 2 parameters, and then exports file in original location adding some "copy"/"-01" to name. The deletion logic should work like "delete X frames after each Y frames".
For example:
= GIF with 22 frames, parameters are X=2 Y=3, after processing there will be: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
= GIF with 22 frames, parameters are X=1 Y=4, after processing there will be: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22
[crossed frames are deleted]
Hope for your help.
I've got this script as start:
Code:
image = gimp.image_list()[0]
for (index,layer) in enumerate(image.layers):
if not index%3:
image.remove_layer(layer)
but it only does like 30% of goal.
Pretty close. Something like this:
1. Depends if you work top down of bottom up
Code:
layers=image.layers[:] # Make a copy of the list
layers.reverse() # if working bottom up
2. Select layers
Code:
keep=3
delete=2
stride=keep+delete
deleted_layers=[layer for i in range(keep,len(layers),stride) for layer in layers[i:i+delete]]
At that point you can inspect the contents of
delete_layers to make sure they are the ones
3. Delete them
Code:
for l in deleted_layers:
image.remove_layer(l)
Coded in slo-mo (so to speak) for better readability, a tattooed Python coder would have done a one-liner
@Ofnuts thank you for code. Py scripts need some special variable setting?(data type or smth)
Code:
Error: eval: unbound variable: layers=image.layers[:]
Hi Ofnuts, I'm confused by this line of your suggested code:
(04-03-2023, 02:41 PM)Ofnuts Wrote: [ -> ]
Code:
layers=image.layers[:] # Make a copy of the list
I get that it makes a copy of a list but could it just be:
Code:
layers=image.layers
I thought the ‘layers’ attribute of an image or layer group builds a new Python list and copies into it the IDs of the layers so that gives the plugin it's own private list anyway?
(04-04-2023, 03:30 AM)teapot Wrote: [ -> ]Hi Ofnuts, I'm confused by this line of your suggested code:
(04-03-2023, 02:41 PM)Ofnuts Wrote: [ -> ]
Code:
layers=image.layers[:] # Make a copy of the list
I get that it makes a copy of a list but could it just be:
Code:
layers=image.layers
I thought the ‘layers’ attribute of an image or layer group builds a new Python list and copies into it the IDs of the layers so that gives the plugin it's own private list anyway?
Maybe, and maybe not. The indexation operator
[] is just a call to a
__getitem__() method, so
image.layers could be live-wired into the image layers, retrieving layers on the fly when
__getitem__() is called. In other words it's indexable but not necessarily a list. And in that case iterating the collection while deleting stuff in it is not going to be pretty.
Of course, in this particular case, it is a list, so yes, the copy isn't entirely necessary.
(04-04-2023, 07:26 AM)Ofnuts Wrote: [ -> ] (04-04-2023, 03:30 AM)teapot Wrote: [ -> ]Hi Ofnuts, I'm confused by this line of your suggested code:
(04-03-2023, 02:41 PM)Ofnuts Wrote: [ -> ]
Code:
layers=image.layers[:] # Make a copy of the list
I get that it makes a copy of a list but could it just be:
Code:
layers=image.layers
I thought the ‘layers’ attribute of an image or layer group builds a new Python list and copies into it the IDs of the layers so that gives the plugin it's own private list anyway?
Maybe, and maybe not. The indexation operator [] is just a call to a __getitem__() method, so image.layers could be live-wired into the image layers, retrieving layers on the fly when __getitem__() is called. In other words it's indexable but not necessarily a list. And in that case iterating the collection while deleting stuff in it is not going to be pretty.
Of course, in this particular case, it is a list, so yes, the copy isn't entirely necessary.
Thank you for your explanation.