How to get the full path from a GFile

[nmw01223]

Development on Windows 11 using python 3 in Gimp 3.0.6.

I can find no way of getting the path from a GFile returned from the parameter setting dialog in a plugin.

A file parameter is created by

Code:

procedure.add_file_argument("src-folder",
                "Source folder",
                "Location of files to parse",
                Gimp.FileChooserAction.CREATE_FOLDER,
                False,
                None,
                GObject.ParamFlags.READWRITE)

The purpose of this is to allow browsing for a directory. It shows up in the plugin dialog as a directory browser, and a directory can be selected.

The parameter is then obtained after the dialog has run as

Code:

src_gfile = config.get_property("src-folder")

This has returned a GFile, not (unfortunately) a string path. The question is, how do I get the path out of the GFile? (I need it because I need to do some manipulations on it).

I've tried various things - src_gfile.get_path() produced nothing (though in another plugin I looked at it clearly did looking at the code, but that may have been on Linux, not Windows). I did find that if in the python console I create a GFile and get the path as

Code:

file = Gio.File.new_for_path("C:\\a\\b\\c")
file.get_path()

I do get the path as 'C:\a\b\c' - but not when it comes from the config as above.

src_gfile.get_uri() does produce the URI as a string, looking something line 'file:\\\C:\a\b\c'. Being a URI, it has the scheme on the from, and I can lose the 'file:\\\' by editing the string, but can't help feeling that is a bodge, certainly not cross platform.

I then found query_info(). So I tried

Code:

file_info = src_gfile.query_info("standard::*", Gio.FileQueryInfoFlags.NONE, None)
file_info.get_display_name()

I do get something back - but it's only the final leaf, ie 'c', not the full path and I can't find any method that does that.

So, basically, I can find no way of tidily get the full path as a string from a GFile. Can anyone help?