(05-03-2023, 10:17 AM)rich2005 Wrote: Surely the answer is: Anything you like
Maybe better visualised as this, a sliding window, so eventually the offset position = zero
then if a 'cell' C = (space + line)
the "equivalent" number of cells = the integer of 'window width' / cell (I)
remainder of space S = 'window width' - I x C
total of space = I x space width + S
Good start, but eventually wrong (I went through that stage, too :-) )
The number of complete celles is the integer division of the window width, minus the offset, by a "cell". Then you have to figure out what it on the left and what is on the right (which depends on offset and grid thickness).